2x^-6x^2=

Solution for 2x^-6x^2= equation:

2x^-6x^2=

We move all terms to the left:

2x^-6x^2-()=0

We add all the numbers together, and all the variables

-6x^2+2x=0

a = -6; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-6)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-6}=\frac{-4}{-12}
=1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-6}=\frac{0}{-12}
=0
$